0=(usinθ)2−2gH0 equals open paren u sine theta close paren squared minus 2 g cap H 2gH=u2sin2θ2 g cap H equals u squared sine squared theta
v=Tμv equals the square root of the fraction with numerator cap T and denominator mu end-fraction end-root Comprehensive Summary Table Unit / Chapter Derivation Topic Final Expression Trajectory of a Projectile Kinematics Horizontal Range Laws of Motion Maximum Velocity on Banked Road Work & Energy Potential Energy of a Spring Gravitation Escape Velocity Properties of Fluids Ascent Formula (Capillary Rise) Properties of Fluids Terminal Velocity Thermodynamics Mayer's Formula Oscillations Simple Pendulum Time Period Complete PDF Reference Guide
m1(Xcm−x1)=m2(x2−Xcm)m sub 1 open paren cap X sub c m end-sub minus x sub 1 close paren equals m sub 2 open paren x sub 2 minus cap X sub c m end-sub close paren
Wnet=(P1−P2)Δmρcap W sub n e t end-sub equals open paren cap P sub 1 minus cap P sub 2 close paren the fraction with numerator delta m and denominator rho end-fraction The change in potential energy ( ) of the fluid mass is: all important derivations of physics class 11 pdf download
Class 11 Physics serves as the cornerstone for engineering, medical, and various other science-related entrance exams. Unlike Class 10, physics here shifts from qualitative understanding to rigorous quantitative analysis. A significant portion of this involves mastering .
To prevent vehicles from skidding on curved paths, roads are tilted upward at the outer edge by an angle be the normal reaction, be friction, and be the mass of the vehicle. Resolving vertical forces: Resolving horizontal forces providing centripetal force: Divide the horizontal equation by the vertical equation:
Can I provide a sample for the banked road or projectile range equations? Share public link 0=(usinθ)2−2gH0 equals open paren u sine theta close
m1(u1−v1)(u1+v1)=m2(v2−u2)(v2+u2)--- (Eq. 2)m sub 1 open paren u sub 1 minus v sub 1 close paren open paren u sub 1 plus v sub 1 close paren equals m sub 2 open paren v sub 2 minus u sub 2 close paren open paren v sub 2 plus u sub 2 close paren space --- (Eq. 2) Dividing Equation 2 by Equation 1:
sinθ+μcosθcosθ−μsinθ=v2Rgthe fraction with numerator sine theta plus mu cosine theta and denominator cosine theta minus mu sine theta end-fraction equals the fraction with numerator v squared and denominator cap R g end-fraction Divide the numerator and denominator by
The minimum velocity required for a body to escape Earth's gravitational pull permanently. Work done to move a mass away by distance Total work to move it from surface to infinity ∞infinity To prevent vehicles from skidding on curved paths,
Deriving a formula helps you understand the 'how' and 'why' behind the physical phenomenon.
This list follows the NCERT/CBSE syllabus. Tick off each as you master it.
) against this restoring force to change the spring's length by an infinitesimal distance